Math, asked by bcakhilsree3101, 6 months ago

find the equation of line passing through A(1,2) B(1,-2)

Answers

Answered by Anonymous
3

\boxed{\underline{\underline{\bf{\star\:Answer}}}}\\\\\\\textsf{y+4x-6=0}\\\\\\\boxed{\underline{\underline{\bf{\star\:Step-by-step\: explanation}}}}\\\\\\\underline{\textsf{Given}}\\\\\textsf{Point\:A\:=\{1,2\}}\\\textsf{Point\:A\:= \{1,2\}}\\\\\textsf{So,}\\\textsf{$x_1=1$}\\\textsf{$y_1=2$}\\\textsf{$x_2=1$}\\\textsf{$y_2=-2$}\\\\\\\boxed{\underline{\underline{\bf{\star\:To\:Calculate}}}}\\\\\\\textsf{Equation\:of\:line\:passing\:through\:A\:and\:B}\\\\\\

\boxed{\star\:\underline{\underline{\bf{Steps}}}}\\\\\\\textsf{Slope\:=\:$\frac{y_2-y_1}{x_2-x_1}$}\\\\\textsf{Substituting\:the\:value\:$x_1,x_2,y_1$\:and\:$y_2$\:in\:the\:above\:formula}\\\\\textsf{Slope\:=\:$\frac{-2-2}{1-1}$}\\\Longrightarrow{\textsf{Slope\:=\:-\:4}}\\\\

We know that,

\texttt{Equation\:of\:line\:passing\:through\:two\:points\:}\\\Longrightarrow{\texttt{y\:-\:$y_1$\:=\:m\:(\:x\:-\:$x_1$\:)}}\\\\\textsf{Substituting\:values\:of\:$x_1,y_1$\:and\:m\:in\:the\:above\:equation}\\\\

y-2=-4(x-1)

y-2=-4x=4

y+4x-6=0

y+4x-6=0 is the required answer.

Some Other Formulas

  • Equation of a line parallel to x-axis at a distance b.

          y=b (where b is constant)

  • Equation of a line parallel to y-axis at a distance a.

          x=a (where a is constant)

  • Equation of line in slope intercept form

          y=mx+c (where m is slope and c is intercept made by line on y-axis)

  • Equation of line in point-slope form or one-point form

         y-y_1=m(x-x_1)

  • Equation of a non-vertical line passing through two given points

        A(x_1,y_1)\:and\:B(x_2,y_2)\:is

         y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

         This is called two-point form.

        We \:can \:also\:write\:m\:instead\:of\:\frac{y_2-y_1}{x_2-x_1}\:

  • Condition of two lines to be parallel is that the slope of the two lines must be equal.

       m_1=m_2

  • Condition of two lines to be perpendicular is that the product of slopes of the two lines must be equal to -1.

        m_1 \times m_2=-1

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