Question

A racing car has a uniform acceleration of 4 m/s^1. What distance will it cover in 10 s after start

Answer 1

$\huge\star\sf\underline\pink{Solution :-}$

$\sf\underline\red{ Given:-} \\ \\ \sf{Initial\: velocity (u) = 0} \\ \\ \sf{ Acceleration (a) = 4\:m/s^2} \\ \\ \sf{Time\:Taken (t) = 10s} \\ \\ \\ \sf\underline\red{To\:Find:-} \\ \\ \sf{ \: \: \: \bullet{ Distance (s) = ?}} \\ \\ \\ \sf\underline\green{Equation\:of\: Motion :-} \\ \\ \longrightarrow\blue{\boxed{\sf{ s = ut + \dfrac{1}{2} at^2 }}} \\ \\ \sf{Putting\:values\:into\: Formula,} \\ \\ \implies{\sf{ s = 0 \times 10 + \dfrac{1}{2} \times 4 \times (10)^2 }} \\ \\ \\ \implies\sf{ s = 0 + 2 \times 100} \\ \\ \\ \implies\sf{ s = 200 \:m} \\ \\ \sf{Hence,} \\ \\ \sf\orange{The\: distance\: covered\:by\:the\: racing\:car\:in} \\ \sf\orange{10s\:is\:200\: metres.}$

$\\ \sf\underline\purple{Additional\: Information:-} \\ \\ \\ \underline\pink{\boxed{\sf{Equation\:of\: Motion:-}}} \\ \\ \longrightarrow\green{\boxed{\sf{ v = u + at}}} \\ \\ \longrightarrow\green{\boxed{\sf{ s= ut + \dfrac{1}{2} at^2}}} \\ \\ \longrightarrow\green{\boxed{\sf{ v^2 = u^2 + 2as}}}$

Answer 2

⠀⠀⠀⠀$\huge \bold \red{ \underline{Soution:-}}$

⠀⠀⠀⠀⠀⠀⠀⠀Here:-

Distance covered, s=? (to be calculated)

⠀⠀⠀⠀⠀⠀Initial velocity, u=0

⠀⠀⠀⠀⠀Acceleration, a=4m s- 3

⠀⠀⠀⠀⠀⠀⠀⠀Time, t=10s

⠀⠀⠀_______________

⠀⠀⠀⠀⠀⟹$\bf\red{s = ut + 1 \: by2 \: at^{2}}$

⠀⠀⟹$\bf\pink{s = 0 \times 10 + 1 \: by \: 2 \times 4 \times (10)^{2}}$

⠀⠀⠀⠀⠀⟹$\bf\red{s = 0 + 2 \times 100}$

⠀⠀⠀⠀⠀⠀⟹$\bf\pink{s = 200m}$

⠀⠀⠀_______________

Hopes it helps!!!!