find the equation of line passing through the origin and inclined to the positive x- axis at 45°
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Step-by-step explanation:
Given:-
the origin and inclined to the positive x- axis at 45°
To find:-
Find the equation of line passing through the origin and inclined to the positive x- axis at 45°?
Solution:-
Given point = The origin = (0,0)
Inclination on X -axis with positive = 45°
We know that
The slope m = Tan θ
We have, θ = 45°
m = Tan 45°
m = 1
Slope = 1
We know that
The equation passes through the point (x1,y1) with the slope m is y-y1 = m(x-x1)
we have x1 = 0 and y1 = 0
=> y-0 = 1(x-0)
=> y = 1(x)
=> y = x
or
x-y = 0
Answer:-.
the equation of line passing through the origin and inclined to the positive x- axis at 45 is y = x
or x-y = 0
Used formulae:-
- The slope of an inclination on positive X-axis is m = Tan θ
- The equation passes through (x1, y1) with slope m is y-y1 = m(x-x1)
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