Find the equation of line passing through the point of intersection 3x-y+5=0 and 2x+3y-15=0 and origin
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What is the answer to, Find the equation of the line through the point of intersection of lines x-y-6=0 and 2x+y+3=0 and passing through the point (2,1)?
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Hungenahalli Sitaramarao Badarinath, Ph.D. in Civil Engineering. Maths keeps one mentally active.
Answered Feb 25, 2018
The two lines that intersect each other are given as:
x-y=6 …(1)
2x+y=-3 …(2)
Add (1) and (2), to get 3x = 3 or x = 1.
Put x=1 in (1) to get y = -5
So the two lines intersect at P (1,-5).
The equation of the line joining P and Q (2,1)
(x-1)/(2–1) = (y+5)/(1+5), or
(x-1)/1 = (y+5)/6, or
6x-6 = y+5, or
6x-y-11=0 is the equation of the line PQ.
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3 ANSWERS

Hungenahalli Sitaramarao Badarinath, Ph.D. in Civil Engineering. Maths keeps one mentally active.
Answered Feb 25, 2018
The two lines that intersect each other are given as:
x-y=6 …(1)
2x+y=-3 …(2)
Add (1) and (2), to get 3x = 3 or x = 1.
Put x=1 in (1) to get y = -5
So the two lines intersect at P (1,-5).
The equation of the line joining P and Q (2,1)
(x-1)/(2–1) = (y+5)/(1+5), or
(x-1)/1 = (y+5)/6, or
6x-6 = y+5, or
6x-y-11=0 is the equation of the line PQ.
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