Question

Find the equation of line passing through the points (7,-3) and (2,-2) . If this line meets x-axis at point p and y-axis at point q; find the co ordinates of points p and q

Answer 1

Answer:

x+5y-8=0 and p(8,0) and q(0,8/5)

Step-by-step explanation:

find the slope of the line

which is (y2-y1)/(x2-x1)

we get -1/5

take the point (2,-2)

form the equation

-(x-2) = 5(y+2)

we get the equation on solving

x+5y-8=0

substitute x=0 we get y=8/5

that's a point q

and y=0 we get x=8

that's point q