find the equation of line perpendicular to the line joining the points A(7,-3) and B(2,-2) and passes through the point which divides AB in the ratio 1:3
Answers
Step-by-step explanation:
According to the section formula, the coordinates of the points that divides the line segment joining the points (1,0) and (2,3) in the ratio 1:n is given by {
1+n
n(1)+1(2)
,
1+n
n(0)+1(3)
}={
n+1
n+2
,
n+1
3
}
The slope of the line joining the points (1,0) and (2,3) is m=
2−1
3−0
=3.
We know that two non-vertical lines are perpendicular to each other if and only if their slpoes are negative reciprocals of each other.
Therefore, slope of the line that is perpendicular to the line joining the points (1,0) and (2,3) is =−
m
1
=−
3
1
Now the equation of the line passing through ={
n+1
n+2
,
n+1
3
} and whose slope is −
3
1
is given by, {y−
n+1
3
}=
3
−1
{x−
n+1
n+2
}
⇒3[(n+1)y−3]=−[x(n+1)−(n+2)]
⇒3(n+1)y−9=−(n+1)x+n+2
⇒(1+n)x+3(1+n)y=n+11