Find the equation of line that is perpendicular to 3x+2y=8 and passes through the mid point of the line segment joining (5,-2) and (2,2)
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2x-3y-7=0 this is the equation
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Answer:
3x + 2y =0
2y = -3x +8
y = -3/2x +8/2
slope of the given equation m1= -3/2
slope of required line = m2
lines are perpendicular to each other.
m2 = 2/3
now the line passes through the midpoint of the given points
so,
mid point=( 7/2,0)
as the equation will passes through the midpoint it will be the passing point.
by using formula
y -y1 = m( x-x1)
y -0 = 2/3(x -7/2)
Step-by-step explanation:
answer = 2x -3y -7 =0
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