Question

Find the equation of line that is perpendicular to 3x+2y=8 and passes through the mid point of the line segment joining (5,-2) and (2,2)

Answer 1

2x-3y-7=0 this is the equation

Answer 2

Answer:

3x + 2y =0

2y = -3x +8

y = -3/2x +8/2

slope of the given equation m1= -3/2

slope of required line = m2

lines are perpendicular to each other.

m2 = 2/3

now the line passes through the midpoint of the given points

so,

mid point=( 7/2,0)

as the equation will passes through the midpoint it will be the passing point.

by using formula

y -y1 = m( x-x1)

y -0 = 2/3(x -7/2)

Step-by-step explanation:

answer = 2x -3y -7 =0

plz give me thank