Question

find the equation of line that passes through (-3,-5) and has a slope -1/2.also find the y- intercept of this line.​

Answer 1

Step-by-step explanation:

If any linear equation passes through $(x_1\:,\:y_1)$ point and has a slope = m ; then general formula of the linear equation is :

$\bf \: (y - y _1) = m(x - x_1)$

According to the question,

Given that,

A line that passes through (-3,-5) and has a slope -1/2

So we can write that,

$\bf \: x_1 = - 3 \\ \bf \: y_1 = - 5 \\ \bf \: slope \: \: m = - \frac{ 1}{2} \\ \\ \bf \: so \: qeuation \: is \: \: : \\ \\ \: \: \: \: \: \: \: \bf y - ( - 5) = - \frac{1}{2} \{x - ( - 3) \} \\ \bf \implies \: y + 5 = - \frac{1}{2} (x + 3) \\ \bf \implies \: 2(y + 5) = - x -3 \\ \bf \implies \: 2y + 10 = - x - 3 \\ \bf \implies \: x + 2y + 13 = 0 \\ \\ \: \: \: \: \green{ \boxed{ \bf \: x + 2y + 13 = 0}} \: \pink{\longrightarrow \bf \: answer}$

Our equation is :

$\: \: \: \: \bf \: x + 2y + 13 = 0 \\ \bf \implies \: 2y = - x - 13 \\ \bf \implies \: y = - \frac{x}{2} - \frac{13}{2} \\ \\ \sf \:comparing \:with\:y=mx+c \\ \therefore \: \sf \: the \: y- \: intercept \: of \: this \: line = - \frac{13}{2}$

Answer 2

Answer:

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