find the equation of line through the point(1,3)making an intercept 5 it was a Y axis
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Textbook question answer:-
x1= -3 , y1=k 2and y2= 5 , x2= -2
By using slope
3=y2-y1÷x2-x1
3=(5-k) ÷ (-2)-(-3)
3=(5-k)÷(-2+3)
3=(5-k)÷1
3=5-k
k=5 - 3
k=2
x1= -3 , y1=k 2and y2= 5 , x2= -2
By using slope
3=y2-y1÷x2-x1
3=(5-k) ÷ (-2)-(-3)
3=(5-k)÷(-2+3)
3=(5-k)÷1
3=5-k
k=5 - 3
k=2
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