Question

find the equation of line through the point (5,-3) and perpendicular to Xaxis​

Answer 1

Step-by-step explanation:

x

1

=−3,y

1

=5,m=0 (∵ line is parallel to X-axis)

∴ Equation of line

∴y−y

1

=m(x−x

1

)

⇒y−5=0(x+3)

⇒y−5=0⇒y=5

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Answer 2

The equation perpendicular to x−axis is given by x=k

The line passes through (−2,−1)

⟹k=−2

so the required straight line is x+2=0

The equation perpendicular to x−axis is given by x=2

The line passes through (−2,−1)

⟹k=−2

so the required straight line is x+2=0

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