Question

Find the equation of line which is perpendicular to 2x + V= 0 and passes

Answer 1

Answer:

y=(1/2)x

Step-by-step explanation:

(NOTE: Before solving this problem, I will be using the variable y instead of V, since y is used when talking about graphing)

First, lets put the equation into y=mx+b form, the equation used when graphing a line:

2x + y = 0 (Subtract 2x from both sides)

y = -2x + 0 (Remove the unnecessary "+0")

y = -2x

Now, lets find an equation that is perpendicular to y = -2x. In this equation, -2 is our slope and the equation that is perpendicular to this line has to have a slope that is a reciprocal of -2. Since -2 is equal to -2/1, the reciprocal would be 1/2. So, the slope for our equation that will be perpendicular to y = -2x is 1/2. Knowing this, lets put our slope into y=mx+b (where m is our slope). We would then be let with y=(1/2)x+b. For a line that is perpendicular, the y-intercept (or b), isn't important, so we will leave our equation at y=(1/2)x.

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