Question

Find the equation of locus of a point equidistant from A(2,0) and the Y-axis

Answer 1

Step-by-step explanation:

Take your Rounder.

Insert your pencil.

measure 3cm in the rounder.

place the pointed end on the paper and draw the circle.

The circle drawn will be with diameter of 6 cm.

Answer 2

Answer:

Step-by-step explanation:

Let the point be P(h,k)

Given,

P is equidistant from A(2,0) and the Y axis

⇒  

(h−2)  

2

+K  

2

 

​

=h

⇒(h−2)  

2

+K  

2

=h  

2

              [Squaring]

⇒h  

2

+4−4h+K  

2

=h  

2

 

⇒K  

2

=4(h−1)

Replacing (h.k) with (x,y) we get

y  

2

=4(x−1)