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Find the equation of Locus of a point which is equidistant from the points, A(-3,2) and B(0,4).
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Answer:
Let the point be (h,k).
Given:
Distance of point from A=Distance of point from B
⟹ (h+3) 2
+(k−2)
2
= h 2 +(k−4)
2
⟹(h+3) 2 +(k−2) 2=h
2+(k−4) 2
⟹h
2+6h+9+k
2
−4k+4=h
2 +k
2 −8k+16
⟹6h−4k+13=−8k+16
⟹6h+4k=3
Replacing h with x and k with y:
6x+4y=3
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