Question

find the equation of locus of a point which is equidistant from the points A(-3,2) and B(0,4)​

Answer 1

Step-by-step explanation:

Given:-(-3,2),(0,4)

Here To find:-Equation to the locus of the point equidistant.

Let us suppose the point be (h,k)

Distance of the point A= Distance of point B

==>(√h+3)^2+(k+2)^2=h^√2+(k-4)^2

==>(h+3)^2+(k+2(^2=h^2+(k-4)^2

==>h^2+6h+9+k^2-4k+4=h^2+k^2-8k+16

==>6h-4k+13=8k+16

==>6h+4k=3

replacing h with x and k with y:

6x+4y=3

hope it helps you