Question

find the equation of locus of the points whose distance from the coordinates axes are in the ratio 2:3 find the answer for this question​

Answer 1

Step-by-step explanation:

let the ratio of 2:3 be a and b

a/b=2/3 (cross multiplication)

2a=3b

taking a=x and b=y

(2x=3y)

4x^2=9y^2

4x^2-9y^2=0

therefore the locus = 4x^2-9y^2=0

I hope this answer will help u

Answer 2

Concept Introduction:-

It might resemble a word or a number representation of the quantity's arithmetic value.

Given Information:-

We have been given that the points whose distance from the coordinates axes are in the ratio $2:3$.

To Find:-

We have to find that the equation of locus of the points whose distance from the coordinates axes are in the ratio $2:3$.

Solution:-

According to the problem

Let the ratio of $2:3$ be $a$ and $b$

$a/b=2/3$ (cross multiplication)

$2a=3b$

taking $a=x$ and $b=y$

$(2x=3y)\\4x^2=9y^2\\4x^2-9y^2=0$

Therefore the locus$= 4x^2-9y^2=0$

Final Answer:-

The correct answer is $4x^2-9y^2=0$.

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