find the equation of normal to the curve y = x2 – 2x + 1 at the point (-1, 4).
Answers
Answered by
1
Step-by-step explanation:
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Answered by
0
Step-by-step explanation:
y=x^2-2x+1 at(-1,4)
first dy/dx=2x-2
(dy/dx)at (-1,4)=2(-1)-2=-4
therefore
equation of Normal is:
-1/(dy/dx)=-1/(-4)
(y-4)=1/4(X+1)
4y-16=X+1
X+17-4 y=0 is required equation.
I hope you get answer.
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