Question

Find the equation of parabola whose vertex is (4,2) and focus is (6,2)?

Answer 1

Hi friend!!

Given,

vertex of a parabola=(4,2)

Focus of a parabola=(6,2)

Now, The axis is parrallel to X-axis

'a' is the distance from vertex to focus

→a=2

Now, equation of the parabola is (y-k)²=4a(x-h)

where (h,k) is the vertex

→equation of the parabola is (y-2)²=8(x-4)

I hope this will help you ;)

Answer 2

Step-by-step explanation:

Equation is 4x2+4xy+y2-76x+62y+161=0