Question

Find the equation of perpendcular bisec of ab where a and b are a

Answer 1

Answer:

Given that A=(3,6) and B=(-3,4)

The equation of perpendicular bisector of AB is the locus of the points which are equidistant from A and B.

Let a point on the perpendicular bisector=P=(x,y)

PA=PB

PA²=PB²

(x-3)²+(y-6)²=(x+3)²+(y-4)²

x²+3²-2(3)(x)+y²+6²-2(6)(y)=x²+3²+2(3)(x)+y²+4²-2(y)(4)

9-6x+36-12y=9+6x+16-8y

12x+4y-20=0

4(3x+y-5)=0

3x+y-5=0

Hence 3x+y-5=0 is the equation of the perpendicular bisector of AB where A=(3,6) and B=(-3,4).