Question

Find the equation of plan which is parallel to the plane x +2y-2z and at a distance of 2 unit from the point (2,1,1)​

Answer 1

Answer:

Step-by-step explanation:

Let the other plane parallel to given plane is,

x−2y+2z+d=0x-2y+2z+d=0

As this plane is unit distance from (1,2,3)

1=±1∗1−2∗2+2∗3+d12+22+22

1=±3+d31=±3+d3

Solving above, we get d=−6d=-6 and d=0d=0

So, equation of planes are:

x−2y+2z=0x-2y+2z=0 and x−2y+2z−6=0

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