Question

Find the equation of set of points which are equidistant from the
points (1,2,3 ) (3, 2, -1)?

Answer 1

Answer:

Let points are (x, y, z)

a/q

${(x - 1)}^{2} + {(y - 2)}^{2} + {(z - 3)}^{2} = {(x - 3)}^{2} + {(y - 2)}^{2} + {(z + 1)}^{2}$

${x}^{2} - 2x + 1 + {z}^{2} - 6z + 9 = {x}^{2} - 6x + 9 + {z}^{2} + 2z + 1$

$- 2x - 6z + 10 = - 6x + 2z + 10 \\ 6x - 2x - 6z - 2z = 0 \\ 4x - 8z = 0$

so required eq. of set of points is

4x – 8z = 0

Ans.