Question

Find the equation of straight line joining the point of intersection 3x + y + 2 = 0 and x – 2y -4 = 0

to the point of intersection of 7x – 3y = -12 and 2y = 4 + 3.​

Answer 1

Answer:

$y - \frac{11}{2} x + 2 = 0$

Step-by-step explanation:

intersection of the first two line will be as follows :

$3x + y + 2 = 0$

$x - 2y - 4 = 0$

multiply above equation by 3 and solve

.........

By solving we get :

y = -2

X = 0

.........

now for last two line we will find the intersection intersection:

given

2y = 7

y = 3.5

X = -1.5

..................

Equation can be found by two point form :

equation :

$y - \frac{11}{3} x + 2 = 0$