Question

Find the equation of straight line passes through the points (-4,6)and (8,-3)

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The equation of straight line passes through the points ( - 4,6)and (8, - 3) is 3x + 4y = 12

Given :

The points ( - 4,6)and (8, - 3)

To find :

The equation of straight line passes through the points

Solution :

Step 1 of 2 :

Write down the given points

The given points are ( - 4,6)and (8, - 3)

Step 2 of 2 :

Find the equation of straight line passes through the points

The required equation of the line is given by

$\displaystyle \sf{ \frac{y - 6}{x - ( - 4)} = \frac{ - 3 - 6}{8 - ( - 4)} }$

$\displaystyle \sf{ \implies \frac{y - 6}{x + 4} = \frac{ - 3 - 6}{8 + 4} }$

$\displaystyle \sf{ \implies \frac{y - 6}{x + 4} = \frac{ - 9}{12} }$

$\displaystyle \sf{ \implies \frac{y - 6}{x + 4} = \frac{ - 3}{4} }$

$\displaystyle \sf{ \implies 4y - 24 = - 3x - 12}$

$\displaystyle \sf{ \implies 3x + 4y = 24 - 12}$

$\displaystyle \sf{ \implies 3x + 4y = 12}$

The equation of straight line passes through the points ( - 4,6)and (8, - 3) is 3x + 4y = 12