Question

find the equation of straight line passing through the point (3,-4) and perpendicular to the line 3x+5y-21=0​

Answer 1

SOLUTION

TO DETERMINE

The equation of straight line pa'ssing through the point (3,-4) and perpendicular to the line 3x + 5y - 21 = 0

EVALUATION

Here the given equation of the line is

3x + 5y - 21 = 0

Now the equation of the line perpendicular to the given line is

5x - 3y + c = 0 - - - - - (1)

Now the Equation 1 goes through the point (3, - 4)

So we get

15 + 12 + c = 0

⇒ 27 + c = 0

⇒ c = - 27

Hence the required equation of the line is

5x - 3y - 27 = 0

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$Find the point where the graph of 0.25x + 0.05y =1.00 intersects the y-axis:

https://brainly.in/question/26332017

2. Find the equation of straight line passing through the point (-4,5) and making equal intercepts on the coordinate axis.

https://brainly.in/question/25257443

3. Find the slope of the line perpendicular to the line AB, if A is (3, 3) and B is (-1, 1)

https://brainly.in/question/27031626