Find the equation of tangent and
normed at any pourt
% = 2 cos 3t
Ligsajour curve given by
the x=2cos3t
and y= 3 sinnt
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Answer:
Explanation:
x=sin3t y=cos2t at t=
4
π
dt
dy
=−2sin2t
dt
dx
=3cos3t
dt
dx
dt
dy
=
3cos3t
−2sin2t
[
dx
dy
]
t=
4
π
=
3cos3×
4
π
−2sin2⋅
4
π
=
3cos
4
3π
−2sin
2
π
=
3
2
2
x=sin3t=sin
4
3π
=
2
1
y=cos2t=cos
2
π
=0
The equation of the tangent
y−0=
dx
dy
(x−
2
1
)
y=
3
2
2
(x−
2
1
)
2
2
x−3y=2.
HOPE THIS HELPS U
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