Question

find the equation of tangent to curve y=2x²-x+3 at (1,3)​

Answer 1

slope= dy/dx= 4x-1+0

substituting the val. of x= 1

slope= 3

EQ:

y-y1=m(x-x1)

y-3= 3(x- 1)

y-3= 3x-3

y-3x=0

(ps the point given is not on the curve)

hope it helps

comment if any doubt