Question

Find the equation of tangent to the curve =

2

at (−1,1)​

Answer 1

Answer:

Step-by-step explanation:

The slope of the tangent to the curve y=f(x) at a point (x,y) is given by  

dx

dy

​

 

2x  

2

+3y  

2

=5

⟹4x+6y  

dx

dy

​

=0

⟹  

dx

dy

​

=  

3y

−2x

​

 

AT(1,1),  

dx

dy

​

=  

3

−2

​

 

Equation of line passing through (1,1) and having a slope of  

3

−2

​

 is given as

y−1=  

3

−2

​

(x−1)

⟹2x+3y=5