Question

Find the equation of tangent to the curve =
2

at (−1,1)​

Answer 1

Answer:

Slope of the tangent to the curve at any point (x,y)=

dx

dy

at (x,y)

dx

dy

=

dx

d(3x

2

)

=6x

At (1,1), the slope of the tangent would be 6

Hence, the equation of line passing through (1,1) and having a slope of 6 is given by

y−1=6(x−1)

⇒6x−y=5

Answer 2

$\mathbb\orange{BRAINLIEST \: ANSWER}$

$\mathbb\red{refers \: to \: attachment}$