Find the equation of tangent to the curve y= 3x−2 which is parallel to the line 4x−2y+5=0. Further find the equation of the normal to the curve. *PLZ ANSWER FAST AND CORRECTLY I'LL MARK AS THE BRAINEST...
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Answer:
The slope-intercept form of a line is given by
y
=
m
x
+
b
where
m
is the slope and
b
is the y-intercept. Our equation needs to be rearranged into this form. We are starting with:
4
x
+
2
y
−
5
=
0
First, we'll move the
4
x
and the constant
−
5
to the other side (by adding
−
4
x
+
5
to both sides):
2
y
=
−
4
x
+
5
Now, we divide both sides of the equation by
2
to get
y
all by itself:
y
=
−
2
x
+
5
2
By comparing this equation to the slope intercept form we can see that
m
=
−
2
,
b
=
5
2
Step-by-step explanation:
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