Question

Find the equation of tangent to the curve y= 3x−2 ​ which is parallel to the line 4x−2y+5=0. Further find the equation of the normal to the curve. *PLZ ANSWER FAST AND CORRECTLY I'LL MARK AS THE BRAINEST...

Answer 1

Answer:

The slope-intercept form of a line is given by

y

=

m

x

+

b

where

m

is the slope and

b

is the y-intercept. Our equation needs to be rearranged into this form. We are starting with:

4

x

+

2

y

−

5

=

0

First, we'll move the

4

x

and the constant

−

5

to the other side (by adding

−

4

x

+

5

to both sides):

2

y

=

−

4

x

+

5

Now, we divide both sides of the equation by

2

to get

y

all by itself:

y

=

−

2

x

+

5

2

By comparing this equation to the slope intercept form we can see that

m

=

−

2

,

b

=

5

2

Step-by-step explanation:

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