Math, asked by sorv67, 1 year ago

find the equation of tangents to the circle x2+y2=10 at the points whose abscissa is 1.

Answers

Answered by NishantDixit
1

H^2=p^2+b^2 13^2=p^2+12^2 169-144=p^2 P=5  Area=1÷2×b×h         =1÷2×12×5         =30 cm^2

Answered by xcristianox
54

  • The radius of the circle is v3.
  • The two points are: +v2:1, -v2:1.
  • If z is the angle of one of the tangents, then sin(z) = v2/v3 = v3/y,
  • where y is the ordinate of one of the tangents.
  • This tangent, therefore is the st line connecting the points (3/v2,0) and (v2,1).
  • The other tangent is the line connecting the points (-3/v2,0) and (-v2,1).

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