Math, asked by lizarizvi333, 1 year ago

find the equation of the circle the endpoints of whose one diameter are the centres of the circle X2 + Y2 + 6 x - 14 Y + 5 =0and X2 + Y2 - 4 x + 10 Y + 7=0

Answers

Answered by Prabhnoor2345

0

Step-by-step explanation:

X2+X2+X6-14Y+5=0

X2 + Y2 - 4 x + 10 Y + 7=0

X2 + Y2 + 6 x - 14 Y + 5= X2 + Y2 - 4 x + 10 Y + 7=0

10x-24y=0

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