Question

Find the equation of the circle which passes through the points
(2,-2), (3, 4) and has its centre on the line 2x + 2y = 7​

Answer 1

Answer:

          2x+2y=7

Step-by-step explanation:

midpoint of (2,-2),(3,4)

       =(2+3/2),(4-2/2)

        =5/2, 1

slope from the eqn: 2x+2y=7

     2x+2y=7

         2y=7-2x

          y=(7-2x)/2

slope is -2/2 is equal to -1

so by using a slope and a point find the eqn

          -1 = (1-y)/(5/2 -x)

after solving the above

u will get,

Answer:

2x+2y=7