find the equation of the circle which passes through the points (5,0) and (1,4) and whose center lies on the line x+y-3=0
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slope=(4-0)/(1-5);
slope is (-1);
now new equation,
-1(x-5)=(y-0);
(-x+5)=(y-0);
x+y-5=0;
Hope answer helps you....
please mark as brainliest...plzzzz
slope is (-1);
now new equation,
-1(x-5)=(y-0);
(-x+5)=(y-0);
x+y-5=0;
Hope answer helps you....
please mark as brainliest...plzzzz
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