Find the equation of the circle whose center is at (3,-4)and the line 3x-4y-5=0
cuts the circle at A and B ;wher l(AB)=6.
Answers
Answered by
4
Answer:
x-3)^2+(y+4)^2=25circle with centre (3,-4) and radius r.
(x-3)^2+(y+4)^2=r^2
Attachments:
Similar questions