Math, asked by KeshavChauhan1, 11 months ago

find the equation of the ellipse, with major Axis and passing through the points (4,3)&(-1,4).

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Answered by kamini87
5

The equation of ellipse is 7x^2+15y^2=247.

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Answered by Anonymous
145

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Centre = (0, 0), and major axis that passes through the points (3, 2) and (1, 6).

We know that the equation of the ellipse will be of the form when the centre is at (0, 0) and the major axis is on the y-axis,

(x^2/b^2) + (y^2/a^2) = 1 …. (1)

Here, a is the semi-major axis.

It is given that, the ellipse passes through the points (3, 2) and (1, 6).

Hence, equation (1) becomes

(9/b^2) + (4/a^2) = 1 …(2)

(1/b^2) + (36/a^2) = 1 …(3)

Solving equation (2) and (3), we get

b^2 = 10 and a^2 = 40

Therefore, the equation of the ellipse becomes: (x^2/10) + (y^2/40) = 1

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Hope it's Helpful.....:)

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