Math, asked by arya7mokashi, 4 months ago

Find the equation of the hyperbola referred to its principal axes: whose length of conjugate axis

= 12 and passing through (1, −2)

Answers

Answered by tunisha13r

2

Answer:

Let the equation of the hyperbola referred to principal axes be x²/y²-y²/b²=

Length of conjugate axes =2b=12............

Step-by-step explanation:

10x²/9 - y²/36

=1

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