Question

find the equation of the line containing the points (2,-3)and (0,-3)​

Answer 1

★...answer : y=-3....★

Answer 2

The equation of the line containing the points (2,-3)and (0,-3)​ is y+3=0.

Given:

The points (2,-3)and (0,-3)​

To Find:

We have to find the equation of the line containing the points (2,-3)and (0,-3)​

Solution:

We know that the equation of the line containing two points $(x_{1} ,y_{1} )$ and $(x_{2},y_{2})$ is  $y -y_{1}= \frac{y_{2} -y_{1} }{x_{2} -x_{1} }* (x-x_{1} )$.

Therefore, the equation of the line containing the points (2,-3)and (0,-3)​ is $(y+3)=(\frac{-3+3}{0-2} )*(x-2)$

⇒$y+3=0$

Hence, the equation of the line containing the points (2,-3)and (0,-3)​ is y+3=0.

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