Question

Find the equation of the line parallel to the line joining (7,5) (2,9) and passing through (3, -4)
a) 7x - 4y + 8 = 0 b) 5y + 4x + 8 = 0
c) 7x – 4y – 8 = 0 d) 5y - 4x + 8 = 0

Answer 1

here

slope of line passing through (7,5)&(2,9) is

m=(9-5)/(2-7)

=-4/5

equation of the line having slope -4/5 and passing through (3,-4)is

(y+4)/(x-3)=-4/5

or,5y+20=-4x+12

•°•4x+5y+8=0. is required equation

hope its okey for you

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Answer 2

Ans = (b)

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