Question

find the equation of the line passing through ....​

Answer 1

Answer:√3x-y=0

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Answer 2

Let A be (x,0) (X1,Y1)
Let B be 2,2 √3 (X2,Y2
Slope = tan Θ
Therefore , slope = tan 60 = √3

Using Point slope form of a line , we get:
y-y1 = m(x-x1)
Now on substituting the data:
0-2 √3= √3(x-2)
2 √3= √3x-2 √3
2 √3+ 2 √3 = √3x
2(√3+ √3) = √3x
2*3 = √3x
6= √3x
6/√3= x
Now rationalise ,
6* √3/ √3* √3= x
6* √3/3=x
2* √3=x
Or
2*1.732=x
3.464=x