Find the equation of the line passing through (-3,-5) and parallel to x-2y-7=0
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Since both the line and the plane are parallel.. There drs are same.
So the Dr of the plane is (1,-2,-7) and the point is (-3,-5,0)
So the equation is
r= x+3/1 = y+5/-2 = z-0/-7
So the Dr of the plane is (1,-2,-7) and the point is (-3,-5,0)
So the equation is
r= x+3/1 = y+5/-2 = z-0/-7
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