Question

Find the equation of the line passing through (-3, 5) and perpendicular to the line through the points (2, 5) and (-3, 6).

Answer 1

hey mate

here is your answer

the slope of the line passing through the points (2,5) and (-3,6) is

y2-y1/x2-x1

=>6-5/-3-2

=>-1/5

thus the slope of the line perpendicular to it would be

=>5

hence, the equation of the line=y-y1=m(x-x1)

=y-5=5(x+3)

=y-5=5x+15

=y=5x+20

# be brainly

Answer 2

Answer:

y-5x=20

Step-by-step explanation:

first we will find the slope of the line passing through (2,5) and (-3,6)

m1=y2-y1/x2-x1

6-5/-3-2

m1= -1/5

now the slope for line perpendicular to it is given by:-

m1= -1/m2

so...

m2=5

now we can equate the formula for slope with its value...

y-5/x+3 = 5

y-5 = 5(x+3)

y-5 = 5x + 15

y-5x = 20