Question

find the equation of the line passing through the intersection of the line 2x+3y-4=0 and x-5y+7=0 and having y-intwrcept equal to 1

Answer 1

Hi Mate !!!

The equation of line passing through the intersection of two lines is A1 + K A2 = 0

Where A2 = x -5y+7=0. And A1 = 2x+3y-4=0

Exp:-

K{x-5y+7} +2x +3y-4=0

x ( 2 +k ) -y ( -3+5k) -4+7k = 0 ..... equation 1

It is given that y intercept is 1 that means x = 0

because this point lies in y-axis

Now put x =0. and y = 1 in equation 1

2K - 1 = 0

K = 1/2

Now put value of k in equation 1 to get equation of line passing through the intersection of two lines

5x/2. +y /2 - 1/2 = 0

5x +y -1 =0

Have a great future ahead!!!

Answer 2

heya!!!

here is your answer:

The equation of line passing through the intersection of two lines is A1 + K A2 = 0

Where A2 = x -5y+7=0. And A1 = 2x+3y-4=0

Exp:-

K{x-5y+7} +2x +3y-4=0

x ( 2 +k ) -y ( -3+5k) -4+7k = 0 ..... equation 1

It is given that y intercept is 1 that means x = 0

because this point lies in y-axis

Now put x =0. and y = 1 in equation 1

2K - 1 = 0

K = 1/2

Now put value of k in equation 1 to get equation of line passing through the intersection of two lines

5x/2. +y /2 - 1/2 = 0

5x +y -1 =0

hope it helps!!