Question

Find the equation of the line passing through the point (3,1) and
parallel to the line which joins (3,-2) and (6,4)

Answer 1

Answer:

so slope of parrellel line

y2-y1/x2-x1=m

4-(-2)/6-3=m

m=6/3

m=2

parrellel line have same slope

y-1/x-3=2

2x-6=y-1

2x-y-5=0

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