Question

Find the equation of the line passing through the point (3,-2) with x intercept -4

Answer 1

Let a=-4 & b be the x & y intercepts  respectively then the equation of straight line

$\frac{x}{-4}+\frac{y}{b}=1$  

Since above line passes through the point $(3, -2)$  hence substituting $x=3, y=-2$  in above equation we get

$\frac{3}{-4}+\frac{-2}{b}=1$  

$b=-8/7$

hence the equation of straight line is obtained by substituting $b=-8/7$ in above equation of line

$\frac{x}{-4}+\frac{y}{-8/7}=1$

$2x+7y+8=0$      

Answer 2

❤❤Here is your answer ✌ ✌

$\huge\boxed{\red{\bold{Answer}}}$

$<b>$

Let ,
a=>-4
b=> be the x and y intercepts  respectively then the equation of straight line•
$\huge\underline{\green{\bold{Now}}}$

x/-4 +y/b=1

Since above line passes through the point (3, -2)(3,−2)  hence substituting x=3, y=-2x=3,y=−2  in above equation we get

3/-4 +(-2/b)=1

b=−8/7

hence
The equation of straight line is obtained by substituting b=-8/7b=−8/7 in above equation of line.

x/-4+y/-(8/7)=1

2x+7y+8=0

$\huge\underline{\purple{\bold{thanks}}}$