Question

Find the equation of the line passing through the point (4,5) & perpendicular to the line 7x-5y=420

Answer 1

Answer:

Required line is 5x + 7y = 55

Step-by-step explanation:

The given line is

7x - 5y = 420 ..... (1)

Let any line perpendicular to line (1) be

5x + 7y = k ..... (2),

where k is any constant to be found using other conditions.

Given that, the line (2) passes through the point (4, 5). Then (4, 5) satisfies (2) no. equation.

So 5 (4) + 7 (5) = k

i.e., k = 55

Therefore from (2), we get the required perpendicular line as

5x + 7y = 55