Question

find the equation of the line passing through the point of intersection of the lines 2x+y=5 and x-2y=5 and having a y-intercept equals to -3/7.

Answer 1

I think this must be the solution to your question. Plzz check it out.

Answer 2

$y=\frac{-4x}{21}-\frac{3}{7}$

Step-by-step explanation:

Line 1 : 2x+y=5

Line 2 :  x-2y=5

To find the intersection point plot the given lines on graph

Line 1 : 2x+y=5 -- Red line

Line 2 :  x-2y=5 -- Blue line

Intersection point = (3,-1) (refer the attached figure )

We are given that the line passes through this intersection point whose y-intercept equals to -3/7.

To find the equation of that line we will use two point slope form :

$(x_1,y_1)=(3,-1)$

$(x_2,y_2)=(0,\frac{-3}{7})$

Formula : $y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

Substitute the values :

$y+1=\frac{\frac{-3}{7}+1}{0-3}(x-3)$

$y+1=\frac{-4}{21}(x-3)$

$y=\frac{-4x}{21}-\frac{3}{7}$

Hence The equation of the line passing through the point of intersection of the lines 2x+y=5 and x-2y=5 and having a y-intercept equals to -3/7 is $y=\frac{-4x}{21}-\frac{3}{7}$

#Learn more :

Point of intersection

Two point slope form

https://brainly.in/question/1661755# : Pinquancaro