how to construct √9.3 on no.line
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not possible there...on this
yashkumar:
but sir it is possible
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4
1. draw a line AB=9.3cm.
2. extend AB 1cm and mark it as C.
3. make perpendicular bisector of AC & mark it as O.
4. taking O as center and AO as radius make a semi circle in AC.
5. make 90° angle on B that meets the semi circle at D.
6. taking BD as radius meke an arc on AC from B and mark it as √9.3
2. extend AB 1cm and mark it as C.
3. make perpendicular bisector of AC & mark it as O.
4. taking O as center and AO as radius make a semi circle in AC.
5. make 90° angle on B that meets the semi circle at D.
6. taking BD as radius meke an arc on AC from B and mark it as √9.3
great
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