Question

find the equation of the line passing through the points A(2,0) and B(3,4)​

Answer 1

Answer:

y-y1= y2-y1/x2-x1 (x-x1)

y-0 =4-0/3-2 (x-2)

y=4/1 (x-2)

y=4x-8

4x-y=8

So, equation of line is 4x-y=8.

Answer 2

Answer:

The equation of the line passing through the points A(2,0) and B(3,4) is

$4x-y-8=0$

Step-by-step explanation:

The equation of the line passing through the points

A(2,0) and B(3,4)​

($x_{1},x_{2}$)=(2,0)

($y_{1},y_{2}$)=(3,4)

$\frac{x-x_{1}}{x_{2}-x_{1} } =\frac{y-y_{1} }{y_{2}-y_{1} }$

This is the formula for passing through the points

$x_{1} =2\\\x_{2}= 3\\y_{1}=0\\y_{2}=4$

$\frac{x-x_{1}}{x_{2}-x_{1} } =\frac{y-y_{1} }{y_{2}-y_{1} }$

Substitute the values in the above equation

$\frac{x-2}{3-2} =\frac{y-0}{4-0}$

$\frac{x-2}{1} =\frac{y-0}{4}$

By cross multiplication

$4(x-2)=1(y-0)$

$4x-8=y$

$4x-y-8=0$

The equation of the line passing through the points A(2,0) and B(3,4) is

$4x-y-8=0$