Question

find the equation of the line perpendicular to the line x-7y+5=0 and having x- intercept 3.​

Answer 1

Answer:

7x + y - 21 = 0

Step-by-step explanation:

Just FYI

$y=m_{1}x + b_{1}$

$y = m_{2}x + b_{2}$

"m" is slope and "b" is y-intercept.

Slopes and of perpendicular lines are opposite reciprocals: $m_{1} m_{2} = -1$

$y - y_{1}=m(x- x_{1})$

~~~~~~~~~

x - 7y + 5 = 0 ⇔ y = (1/7)x + (5/7) ⇒ $m_{1} = \frac{1}{7}$

Slope of perpendicular line is $m_{2} = - 7$ and line is passing through the point (3, 0)

y - 0 = - 7( x - 3)

y = - 7x + 21 ⇔ 7x + y - 21 = 0