Find the equation of the line that cuts off eqwual intercepts of the co ordinate axes a passes through th point (2,3)
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Given:-
- The equation of the line that cuts off eqwual intercepts of the co ordinate axes a passes through th point (2,3)
To find:-
- Find the equation of a line...?
Solutions:-
The equation of a line in the intercept from is x/a + y/b = 1 ..........(i).
Here, a and b are the intercept on x and y axis respectively.
It is given that the line cuts off equal intercepts on both the axis.
- a = b
Accordingly, equation (i). reduces to
=> x/a + y/a = 1
=> x + y = a ............(ii).
Since the given line passes through points (2, 3) equation (ii). reduces to.
=> x + y = a
=> 2 + 3 = a
=> a = 5
On substituting the value of a in equation (ii), we obtain.
=> x + y = 5
Hence, x + y = 5 is the required equation of the line.
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