Question

Find the equation of the line that is perpendicular to 2y+5x−6=0 and bisects the line joining the points P(4,3) and (−6,1). Select one: A. 2y−5x−9=0 B. 5y−2x−12=0 C. 5y+2x−8=0 D. y+5x+3=0

Answer 1

Answer:

5y +2x -8 = 0

Step-by-step explanation:

let the eqn of line be ax + by + c = 0

since line is perpendicular to line 2y + 5x -6 = 0 the slope of the line will be -2/5.

which means -a/b = -2/5 or 5a = 2b or a/2 = b/5

only option c matches this relationship